enzymes convert glucose M=180.2 to ethanol M=46.1 according to the equation C6H12O6=2C2H5OH + 2CO2
what is the maximum mass of ethanol that can be made from 15.5 kg of glucose?
7.93 kg
mols glucose = grams/molar mass
Convert mols glucose to mols ethanol using the coefficients in the balanced equation.
Convert mols ethanol to grams ethanol by g = mols x molar mass.
To find the maximum mass of ethanol that can be produced from 15.5 kg of glucose, we need to use the stoichiometry of the reaction.
From the equation C6H12O6 = 2C2H5OH + 2CO2, we can see that 1 mole of glucose (C6H12O6) produces 2 moles of ethanol (C2H5OH).
First, let's calculate the molar masses of glucose and ethanol:
- Molar mass of glucose (C6H12O6) = (6 * 12.01 g/mol) + (12 * 1.01 g/mol) + (6 * 16.00 g/mol) = 180.18 g/mol
- Molar mass of ethanol (C2H5OH) = (2 * 12.01 g/mol) + (6 * 1.01 g/mol) + 16.00 g/mol = 46.08 g/mol
Now, we can set up the following conversion factors:
- 1 mole of glucose = 180.18 g of glucose
- 2 moles of ethanol = 92.16 g of ethanol
To find the number of moles of glucose in 15.5 kg, we can use the molar mass of glucose:
Number of moles of glucose = (15.5 kg * 1000 g/kg) / 180.18 g/mol
Now, let's calculate the maximum mass of ethanol that can be produced by multiplying the number of moles of glucose by the molar mass of ethanol:
Maximum mass of ethanol = (Number of moles of glucose) * (2 moles of ethanol / 1 mole of glucose) * 46.08 g/mol
Substituting the calculated values:
Number of moles of glucose = (15,500 g) / 180.18 g/mol ≈ 86.02 mol
Maximum mass of ethanol = 86.02 mol * (2 mol / 1 mol) * 46.08 g/mol ≈ 7933.04 g ≈ 7.93 kg
Therefore, the maximum mass of ethanol that can be made from 15.5 kg of glucose is approximately 7.93 kg.
To find the maximum mass of ethanol that can be made from 15.5 kg of glucose, we need to use the molar masses and stoichiometry of the reaction.
Given:
Mass of glucose (C6H12O6) = 15.5 kg
Molar mass of glucose (C6H12O6) = 180.2 g/mol
Molar mass of ethanol (C2H5OH) = 46.1 g/mol
Step 1: Convert the mass of glucose to grams.
15.5 kg x 1000 g/kg = 15,500 g
Step 2: Calculate the number of moles of glucose.
Number of moles = Mass (in grams) / Molar mass
Number of moles of glucose = 15,500 g / 180.2 g/mol ≈ 86.03 mol (rounded to two decimal places)
Step 3: Use the stoichiometry of the reaction to determine the number of moles of ethanol.
According to the balanced equation, 1 mole of glucose yields 2 moles of ethanol.
Number of moles of ethanol = 2 x Number of moles of glucose = 2 x 86.03 mol = 172.06 mol
Step 4: Convert the number of moles of ethanol to mass.
Mass of ethanol = Number of moles x Molar mass
Mass of ethanol = 172.06 mol x 46.1 g/mol ≈ 7942.77 g (rounded to two decimal places)
Therefore, the maximum mass of ethanol that can be made from 15.5 kg of glucose is approximately 7942.77 grams or 7.94277 kg.