Problem Solving
Work Backward
The temperature was 16 degree Celsius when Becky returned home at 6 p.m. The temperature was 4 degree Celsius warmer at 3 p.m. than it was at 6 p.m. It was 3 degree Celsius warmer at 12 noon than it was at 3 p.m. What was the temperature at 12 noon?
T at 3pm was 16+4 = 20
T at noon was 20+3 = 23
To solve this problem, we can use a technique called "working backward." We will start from the given information and work our way back in time.
We know that when Becky returned home at 6 p.m., the temperature was 16 degrees Celsius.
Next, we are told that the temperature at 3 p.m. was 4 degrees Celsius warmer than it was at 6 p.m. Therefore, at 3 p.m., the temperature would be 16 degrees Celsius - 4 degrees Celsius = 12 degrees Celsius.
Moving further back, we are also given that the temperature at 12 noon was 3 degrees Celsius warmer than it was at 3 p.m. So, at 12 noon, the temperature would be 12 degrees Celsius + 3 degrees Celsius = 15 degrees Celsius.
Therefore, the temperature at 12 noon was 15 degrees Celsius.
To summarize:
- The temperature at 6 p.m. was 16 degrees Celsius.
- The temperature at 3 p.m. was 12 degrees Celsius.
- The temperature at 12 noon was 15 degrees Celsius.