Matt forgot to put the fabric softener is the wash. As his socks tumbled in the dryer, they became charged.If a small piece of lint with a charge of +1.25 E -19 C is attracted to the socks by a force of 3.0 E -9 N, what is the magnitude of the electric field at this location?
To find the magnitude of the electric field at the location where the lint is attracted to the socks, we can use the equation for the electric field (E), force (F), and charge (q):
E = F / q
Let's plug in the given values:
F = 3.0 E -9 N (force)
q = 1.25 E -19 C (charge)
Now we can calculate the electric field:
E = (3.0 E -9 N) / (1.25 E -19 C)
To simplify this calculation, let's convert the values to scientific notation:
E = (3.0 × 10^(-9) N) / (1.25 × 10^(-19) C)
Now, divide the numbers:
E = 2.4 × 10^10 N/C
Therefore, the magnitude of the electric field at this location is 2.4 × 10^10 N/C.
To find the magnitude of the electric field at the location where the lint is attracted to the socks, we can use the formula:
Electric field (E) = Force (F) / Charge (q)
Given:
Force (F) = 3.0 E -9 N (3.0 x 10^-9 N)
Charge (q) = +1.25 E -19 C (+1.25 x 10^-19 C)
Now, we can substitute the values into the formula to find the electric field:
E = F / q
E = (3.0 x 10^-9 N) / (+1.25 x 10^-19 C)
To divide values in scientific notation, we subtract the exponents:
E = 3.0 / 1.25 x 10^(-9 - (-19)) C
When subtracting exponents, we change the sign and add them:
E = (3.0 / 1.25) x 10^(10) C
Now we can calculate the expression in brackets:
E = (2.4 x 10^9) C
The magnitude of the electric field at that location is 2.4 x 10^9 C, or 2.4 Gigacoulombs (GC).