General Chemistry

The value of delta H for the reaction below is -6536 kJ. ____kJ of heat released in the combutsion of 16.0g of C6H6.

2C6H6(l) + 15O2(g) yield 12CO2(g) + 6H2O

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  1. 6536 kJ x (16.0/2*molar mass C6H6
    dH is -that number. Or it is correct to say that numberr of kJ is released as heat.

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  2. First, Determine the number of moles you have of C6H6 (16 g / molar mass (78)) = .206 Moles C6H6

    Now its good ol stoichiometry

    Using the formula given
    2 moles of C6H6 produce the -6536 kJ

    .206 C6H6 * -6536kJ / 2 moles C6H6 = -673.208 (or so)

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