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posted by Reiny
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Thanks so much your method worked perfectly! My solution was: the remaining zeros were 5+2i, 3, and 4 I have one question that's bugging me though, why is it that synthetic division did not work for me? I thought that long
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Algebra 2 help please :)
What is a cubic polynomial function in standard form with zeros 1, –2, and 2? Use synthetic division to find P(3) for P(x) = x^4 – 6x^3 – 4x^2 – 6x – 2. Divide 3x^3 + 3x^2 + 2x – 2 by x + 3 using long division. Divide
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I am familiar with this type of problem but can't seem to get the right answer. Use the given zero to find the remaining zeros of each function f(x)=x^49x^3+7x^291x348,zero 52i I normally would use synthetic division with the
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Divide using long division or synthetic division. (21x^3  7)/(3x  1) Just wondering, how would you solve this problem using synthetic division?
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