A 45 g block of aluminum initially at 28.0° C absorbs 548 J of heat. What is the final temperature
of the aluminum? The specific heat of aluminum is 0.902 J/g °C.
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q = mass x specific heat x Tfinal-Tinitial)
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To find the final temperature of the aluminum, we can use the formula:
Q = m * c * ΔT
where Q is the heat absorbed, m is the mass of the aluminum, c is the specific heat of aluminum, and ΔT is the change in temperature.
Given:
Mass of aluminum (m) = 45 g
Specific heat of aluminum (c) = 0.902 J/g °C
Heat absorbed (Q) = 548 J
Rearranging the formula, we can solve for ΔT:
ΔT = Q / (m * c)
Substituting the given values:
ΔT = 548 J / (45 g * 0.902 J/g °C)
Now, let's calculate ΔT:
ΔT = 12.99 °C
The change in temperature is 12.99 °C. To find the final temperature, we need to add this change to the initial temperature.
Final temperature = Initial temperature + ΔT
Given initial temperature = 28.0 °C, let's calculate the final temperature:
Final temperature = 28.0 °C + 12.99 °C
Final temperature = 40.99 °C
Therefore, the final temperature of the aluminum is 40.99 °C.
To find the final temperature of the aluminum, we can use the equation for heat transfer:
Q = m * c * ΔT
Where Q is the heat transferred, m is the mass of the aluminum, c is the specific heat capacity of aluminum, and ΔT is the change in temperature.
In this case, the given values are:
Q = 548 J
m = 45 g
c = 0.902 J/g °C
Since we are trying to find the final temperature, we can rearrange the equation and solve for ΔT:
ΔT = Q / (m * c)
Now, let's substitute the values into the equation:
ΔT = 548 J / (45 g * 0.902 J/g °C)
Calculating this gives us:
ΔT ≈ 12.45 °C
Since the initial temperature of the aluminum is 28.0°C, we can find the final temperature by adding the change in temperature to the initial temperature:
Final temperature = 28.0°C + 12.45°C
Final temperature ≈ 40.45°C
Therefore, the final temperature of the aluminum is approximately 40.45°C.