find the vertex of 400-16tsquared
find the x-coordinate using t = b/2a
In your equation, b = 0 and b/2a is 0
Now substitute 0 fot t in the original equation and get y = 400.
The vertex is at (0,400)
In your equation, b = 0 and b/2a is 0
Now substitute 0 fot t in the original equation and get y = 400.
The vertex is at (0,400)