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This has to do with vectors...I'm wondering if I set up the diagram correctly? A plane has a speed of 250mph and flies with a bearing of N35degE. The wind is blowing from the west at 25 mph with a heading of due east. What is the
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a plane starts from a point P and flies 240km on a bearing of 120degrees to Q. At Q the plane makes a 90degree turn and flies back 100km on a bearing of 210degrees to R. At R the plane again changes direction and flies back to P.
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Question is: What is the algebraic equation to determine when they will meet? For the following information, I understand 5(x+y) = 3000 for 1st plane & 10(xy) = 3000 for 2nd plane. When an airplane flies with a given wind, it can
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Question is: What is the algebraic equation to determine when they will meet? For the following information, I understand 5(x+y) = 3000 for 1st plane & 10(xy) = 3000 for 2nd plane. When an airplane flies with a given wind, it can
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A plane starts from point P and flies 240km on a bearing of 120 degrees to Q. At Q the plane makes a 90 degree turn and flies 100km on a bearing of 210 degrees to R. At R the plane again changes directions and flies back to P.
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a plane flies 1.5 hours at 110 mph on a bearing of 10°. it then turns and flies 8.5 hours at the same speed on a bearing of 100°. How far is the plane from its starting point?
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When an airplane flies with a given wind, it can travel 3000 km in 5hrs. When the same airplane flies in the opposite direction against the wind it takes 10hrs to fly the same distance. Find the speed of the plane in still air and
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