physics

A 1100 kg car coasts on a horizontal road with a speed of 19 m/s. After crossing a an unpaved, sandy stretch of road 32 m long, its speed decreases to 12 m/s. (a) Was the net force done on the car positive, negative, or zero? Explain (b) Find the magnitude of the average net force on the car in the sandy section.

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  1. hi answer is pi

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  2. Equations:

    Change in kinetic energy = 1/2m(Vf^2-Vi^2) = Net (total) Work done on the object = F*d

    m = 1100 kg
    Vi = 19 m/s
    Vf = 12 m/s
    d = 32m

    Calculations:

    1/2(1100)(12^2-19^2) = F(net)*32
    =119350/32
    b) =3730 N

    a) ΔEK is negative, meaning that W < 0 meaning that theta > 90 degrees (cos180 for this question)

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