What volume does 3.01 x 10^21 molecules of N2 occupy at STP?

asked by Ryan
  1. divide the molecules by 6.022*10^23 to give you how many moles of gas you have. then multiply that by the fact that 1 mole of any ideal gas at stp occupies a volume of 22.4L. you should get .112L

    posted by Anonymous

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