The water loss by the sample, and the precent by weight of the water in the unknown hydrates 34.78%H2O.
which of the ten possible hydrates are the most likely ones to be your unknown based on the percent by weight?
To determine which of the ten possible hydrates are the most likely ones based on the percent by weight of water in the unknown hydrates (34.78% H2O), we need to compare the percent by weight of water in each hydrate with the given value.
Here's how you can find the most likely hydrates:
1. List the ten possible hydrates.
2. Calculate the percent by weight of water in each of the ten hydrates.
3. Compare the calculated percent by weight with the given value (34.78%).
4. Determine which hydrates have a percent by weight of water closest to 34.78%.
5. Based on the closest matches, identify the most likely hydrates.
Let's assume the ten possible hydrates are labeled as H1, H2, H3, H4, H5, H6, H7, H8, H9, and H10. Here's an example to demonstrate the process:
1. List the ten hydrates:
- H1
- H2
- H3
- H4
- H5
- H6
- H7
- H8
- H9
- H10
2. Calculate the percent by weight of water for each hydrate:
- H1: 30%
- H2: 32%
- H3: 36%
- H4: 38%
- H5: 40%
- H6: 42%
- H7: 44%
- H8: 46%
- H9: 48%
- H10: 50%
3. Compare the calculated values with the given value (34.78%). From the list above, H3 (36%) and H2 (32%) are closest to 34.78%.
4. Based on the closest matches, H3 and H2 are the most likely hydrates.
Please note that the actual hydrates and their respective percent by weight may vary depending on the specific context or problem. Use the same procedure described above to determine the most likely hydrates based on the given percent by weight of water.