algebra

To balance a seesaw, the distance, in feet, a person is from the fulcrum is inversely proportional to the person's weight, in pounds. Peter, who weighs 150 pounds, is sitting 3 feet away from the fulcrum. If Joey weighs 90 pounds, how far from the fulcrum should he sit to balance the seesaw?

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  1. d = k/w
    if w=150 , d = 3
    3 = k/150
    k = 450

    so d = 450/w

    if w = 90
    d = 450/90 = 5

    or

    w1/w2 = d2/d1
    150/90 = d2/3
    d2 = 3(150/90) = 5

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  2. cbdnm nmg

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  3. Rainy is right

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  4. thanks

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  5. Thank you so much, this helped a lot!

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