A bag contains tiles with the letters P-R-O-B-A-B-I-L-I-T-Y. Tyler chooses a tile without looking and doesn’t replace it. He chooses a second tile without looking. What is the probability that he will choose the letter I both times?
Prob = (2/11)(1/10)
= 1/55
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A bag contains tiles with the letters P-R-O-B-A-B-I-L-I-T-Y. Tyler chooses a tile without looking and doesn’t replace it. He chooses a second tile without looking. What is the probability that he will choose the letter I both times?
asked by Probability Math
The probability of choosing the letter I on the first draw is 3/12 or 1/4 (since there are three I's out of 12 letters total). The probability of then choosing another I on the second draw without replacing the first tile is 2/11 (since there are now only two I's left out of 11 total tiles).
Therefore, the probability of choosing the letter I both times is:
(1/4) x (2/11) = 1/22
So the probability of Tyler choosing the letter I both times is 1/22.