Chemistry

Calculate the pH after 0.010 mol gaseous HCl is added to 250.0 mL of each of the following buffered solutions:
a. .050 M NH3/.15 M NH4Cl
b. .5 M NH3/ 1.5 M NH4Cl

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  1. millimols NH3 initial = 250 x 0.05 = 12.5
    mm NH4Cl initial = 250 x 0.15 = 37.5
    add 0.01 mol = 10 mmols HCl.

    .......NH3 + HCl ==> NH4Cl
    I......12.5..0.0.....37.5
    add..........10..........
    C.....-10...-10......+10
    E......2.5....0......47.5

    Substitute the E line into Henderson-Hasselbalch equation and solve for pH.
    b is done the same way.

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