# Alg 1

Simplify each quotient

7/sq rt 2 - sq rt 3

Please solve and explain how you did it. What do you do when the denominator is a negative?

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1. 7/(√2-√3)
since (a-b)(a+b) = a^2-b^2,

= 7/(√2-√3) * (√2+√3)/(√2+√3)
= 7(√2+√3)/(2-3)
= -7(√2+√3)

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