# college physics

a tennis ball is thrown straight up with an initial velocity of 22.5 m/s. it is caught at the same distance above the ground.

a). how long does it take to reach its maximum height?

b). how high does the ball rise?

c). at what speed does it hit the ground?

d). what total length of time is the ball in the air

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1. a. V = Vo + gt
t = -Vo/g = -22.5/-9.8 = 2.3 s.

b. b. V^2 = Vo^2 + 2g*h
h = (V^2-Vo^2)/2g
h = (0-(22,5)^2)/-19.6 = 25.83 m.

c. V^2 = Vo^2 + 2g*h
V^2 = 0 + 19.6*25.83 = 506.27
V = 22.5 m/s.

d. T = Tr + Tf = 2.3 + 2.3 = 4.6 s.

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2. How long will it take the ball to reach the peak of the trajectory?

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3. How high does the ball rise?

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