the volume of 0.220 mol of an ideal gas at 34°C is increased isothermally from an initial volume of 12.0 L.
If the final volume is 21.5 L, calculate the entropy change for the process.
To calculate the entropy change for an isothermal process, we need the equation:
ΔS = nR ln(Vf / Vi)
Where:
ΔS is the entropy change
n is the number of moles of gas
R is the gas constant (8.314 J/(mol·K))
Vf is the final volume
Vi is the initial volume
Given:
n = 0.220 mol
R = 8.314 J/(mol·K)
Vf = 21.5 L
Vi = 12.0 L
We can plug in these values into the equation to calculate the entropy change:
ΔS = (0.220 mol)(8.314 J/(mol·K)) ln(21.5 L / 12.0 L)
Now we can solve the equation using a calculator or computer program.