# physics...

A kayaker paddles due north at 2 m/s. The river the kayaker is paddling in flows towards the east at 1 m/s. After 5 seconds of paddling, how far is the kayaker from where she started in m?

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1. v=sqrt(v₁²+v₂²) = sqrt(4+1) =2.236 m/s
s=vt=2.236•5=11.18 m

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posted by Elena

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