Fe2O3 + 3C = 2Fe + 3CO

How many grams of C are required to react with 2.50 moles of Fe2O3 ?

1

To find out how many grams of C are required to react with 2.50 moles of Fe2O3, you can use the balanced equation and the molar masses of the substances involved.

1. Start by writing the balanced equation:
Fe2O3 + 3C = 2Fe + 3CO

2. Calculate the molar mass of Fe2O3:
2(Fe) + 3(O) = 2(55.85 g/mol) + 3(16.00 g/mol) = 159.69 g/mol

3. Use the molar mass of Fe2O3 to convert moles to grams:
2.50 moles of Fe2O3 x (159.69 g/mol) = 399.23 grams of Fe2O3

4. Now, use the stoichiometry of the balanced equation to determine the required moles of C:
From the balanced equation, we can see that 1 mole of Fe2O3 reacts with 3 moles of C.

2.50 moles of Fe2O3 x (3 moles C / 1 mole Fe2O3) = 7.50 moles of C

5. Finally, calculate the grams of C required using the molar mass of C:
7.50 moles of C x (12.01 g/mol) = 90.08 grams of C

Therefore, 90.08 grams of C are required to react with 2.50 moles of Fe2O3.

To determine the amount of grams of C required to react with 2.50 moles of Fe2O3, we need to use the balanced equation:

Fe2O3 + 3C = 2Fe + 3CO

From the equation, we can see that the stoichiometric ratio between Fe2O3 and C is 1:3. This means that for every 1 mole of Fe2O3, we need 3 moles of C.

To solve the problem, follow these steps:

Step 1: Determine the molar mass of C.
The molar mass of C (carbon) is approximately 12.01 g/mol.

Step 2: Convert moles of Fe2O3 to moles of C.
Since the stoichiometric ratio between Fe2O3 and C is 1:3, we can set up a proportion to find the moles of C.

1 mole Fe2O3 / 3 moles C = 2.50 moles Fe2O3 / X moles C

Cross-multiplying gives us:
1 * X = 3 * 2.50
X = 7.50 moles C

Step 3: Convert moles of C to grams of C.
To convert moles of C to grams, we need to multiply the moles by the molar mass of C.

grams of C = moles of C * molar mass of C
grams of C = 7.50 moles * 12.01 g/mol
grams of C ≈ 90.08 grams

Therefore, approximately 90.08 grams of C are required to react with 2.50 moles of Fe2O3.

2.5 mols Fe2O3 x (3 mols C/1 mol Fe2O3) = ? mols C.

Then grams C = mols C x atomic mass C.