physics

You and your friend, both of mass 70 kg, are playing catch with a frisbee on frictionless ice. Initially, you are both at rest. You throw a 0.175 kg frisbee at 10 m/s horizontally at your friend, who catches it. After they catch the frisbee, what is the relative velocity between you and your friend in m/s?

asked by rohit
  1. m₁=m= 70 kg
    m₃=0.175 kg, v₃=10 m/s
    Let v₃ be positive and directed to the right
    0= - m₁v₁+m₃v₃
    v₁=m₃v₃/m₁=0.175•10/70=0.025 m/s (directed to the left)
    m₃v₃ =(m₂+m₃)v
    v= m₃v₃/(m₂+m₃)=0.175•10/(70+0.175)=0.0249 m/s (directed to the right)
    V(relative) =
    =v₁+v=0.025+0.0249 =0.0499 m/s

    posted by Elena
  2. thankyou

    posted by rohit

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