Two objects with masses 4.90 and 2.10 hang 0.800 above the floor from the ends of a cord 7.20 long passing over a frictionless pulley. Both objects start from rest.

Find the maximum height reached by the 2.10 object.

The heavier object will move .8 m down, the lighter will move up an additional .8m.

max height= initial height+movement up.

but how do u find the initial height?


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  1. Hey Ben,
    alright first you have to determine the acceleration of the system.
    Let m1=2.1kg and m2=4.9kg
    a= (m2-m1)(g)/(m2+m1)
    = (4.9-2.1)(9.8)/ (4.9+2.1)
    =3.92 ms^-2
    Now we must determine the speed of m1
    we use
    we know that m1 was at rest so u=0 m/s
    and also we know that m2 will go all the way down so m1 moves up 0.8m so s=0.8 m
    v^2= 6.272
    v=2.5044 m/s

    Now we know that m1 is (0.8+0.8)m above the ground as m2 goes down to the floor

    So we add 1.6m to the max height

    To calculate max height
    use formula
    = (2.5044)^2/ (2 x 9.8)
    so add 1.6m to max height

    HOPE THIS HELPS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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  2. "so add 1.6m to max height

    Sorry I meant max height is = 0.32+1.60=1.92m

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