# Chemistry

Calculate the standard free-energy change for the following reaction at 25 C degrees.

2Au^3+(aq)+3Ni(s) <-- --> 2Au(s)+3Ni^2+(aq)

Ni2+(aq) + 2e- -> Ni(s) E=-0.26
Au3+(aq) + 3e- -> Au(s) E=+1.498

G= ? KJ

Would it be G=1.758?

•Chemistry - DrBob222, Sunday, March 31, 2013 at 1:35pm
My calculator went out so I can't calculate this. My table gives Ni^2+ ==>Ni as -0.26
So Ecell = 1.498 + 0.26 = ?
dG = -nFE = 6*96,485*Ecell

Chemistry - Anon, Sunday, March 31, 2013 at 2:05pm
I got -1.02*10^6 but it is wrong.

Chemistry - DrBob222, Sunday, March 31, 2013 at 2:30pm
Well, I copied your number instead of what I thought it was so Ecell = 1.49 + (-0.26) = ?
I did this on google and obtained an answer of 717 kJ but you need to go through and clean it up. Especially the number of significant figures. These databases are unforgiving.

Chemistry - Anon, Monday, April 1, 2013 at 12:45am
It is still wrong.

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1. Nvm it was -1.02*10^3 KJ

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posted by Anon

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