Mary made two rectangular prims figures with four-1 inch cubes. Which statement is true about the volumes and surface areas of the two figures.( there is figure A and figure B made out of four cubes but in different position )

A. The surface areas of Figures A and B are the same.
B. The volume of Figure A is greater than the volume of figure B.
C. The surface areas of Figure B is greater than the surface area o Figure A.
D. The volumes of Figure A and B are the same.

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A and D are correct.

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To determine which statement is true about the volumes and surface areas of the two figures, let's analyze the given information.

Both figures, A and B, are made out of four 1-inch cubes, but in different positions. Since each cube has a length, width, and height of 1 inch, we can calculate the dimensions of each figure.

Figure A:
To form Figure A, we need to arrange the four cubes in a rectangular shape. Let's say the dimensions of Figure A are length (L), width (W), and height (H). If we choose L = 2 inches, W = 1 inch, and H = 1 inch, we can arrange the cubes in a 2x1x1 rectangular shape.

Figure B:
For Figure B, we need to arrange the four cubes in a different position, so the dimensions will be different. Let's say the dimensions of Figure B are length (L'), width (W'), and height (H'). If we choose L' = 1 inch, W' = 2 inches, and H' = 1 inch, we can arrange the cubes in a 1x2x1 rectangular shape.

Now, let's evaluate each statement:

A. The surface areas of Figures A and B are the same.
To calculate the surface area of each figure, we need to find the sum of the individual surfaces of the cubes.

Surface area of Figure A = (2x1) + (1x1) + (1x1) + (1x1) = 2 + 1 + 1 + 1 = 5 square inches.

Surface area of Figure B = (1x2) + (2x1) + (1x1) + (1x1) = 2 + 2 + 1 + 1 = 6 square inches.

Since the surface areas of Figure A and Figure B are different (5 square inches and 6 square inches, respectively), statement A is false.

B. The volume of Figure A is greater than the volume of Figure B.
The volume of a rectangular prism is calculated by multiplying its length, width, and height.

Volume of Figure A = 2 x 1 x 1 = 2 cubic inches.

Volume of Figure B = 1 x 2 x 1 = 2 cubic inches.

Since the volumes of Figure A and Figure B are the same (2 cubic inches), statement B is false.

C. The surface area of Figure B is greater than the surface area of Figure A.
As calculated earlier, the surface area of Figure A is 5 square inches, and the surface area of Figure B is 6 square inches. Therefore, statement C is true.

D. The volumes of Figure A and Figure B are the same.
As calculated earlier, the volumes of Figure A and Figure B are both 2 cubic inches. Therefore, statement D is true.

In conclusion, the correct statement is:
C. The surface areas of Figure B are greater than the surface areas of Figure A.

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