algebra
 👍
 👎
 👁

 👍
 👎

 👍
 👎

 👍
 👎

 👍
 👎

 👍
 👎
Respond to this Question
Similar Questions

ALGEBRA WORD PROBLEM! HELP!
And if a length of a rectangle is 3 more than twice the width and the are is 90 cm squared than what are the dimensions of the rectangle? The width of the rectangle is 43.5 and the length of the rectangle is 87. All together when

Calculus
A rectangle has area 64 m2. Express the perimeter of the rectangle as a function of the length L of one of its sides. State the domain of P. (Assume the length of the rectangle is larger than its width. Enter your answer using

algebra
The length of a rectangle is 3 more than twice the width. The area of the rectangle is 119 square inches. What are the dimensions of the rectangle? If x = the width of the rectangle, which of the following equations is used in the

Algebra
you can represent the width of a certain rectangle with the expression x + 2. the length of the rectangle is twice the width. what is the area of the rectangle? A.) 2x+4 B.) 2x^2+8 C.) 2x^2+8x+8 D.) 4x^2+16x+16 I'm not sure on the

algebra
A rectangle has a length that is 10 less than 3 times the width. If the rectangle has an area of 8 square feet, what is the width of the rectangle. I have to find the answer in meters, some please give some assistance.

Math
If the length of a rectangle is (2x1)cm and its width is (x+3)cm. How do i write an expression in the form ax^2+bx+c for the area of the rectangle? Given that the area of the rectangle is 294cm^2, determine the value of x and

coordinate algebra
The area of a rectangle is found by multiplying the length by the width: A = lw. A certain rectangle has an area of x2 + 7x + 12. Factor the trinomial to find the length and width of the rectangle. In the form of a paragraph,

Math 2
The rectangle below has an area of 30k^3+6k^2 The width of the rectangle (in meters) is equal to the greatest common monomial factor of 30k^3 and 6k^2 What is the width and length of the rectangle? Width:6k^2 Length: I couldn't

mathematics
the area of a rectangle is found by multiplying its length times it’s width. what is the area of a rectangle with a length of 2 1/4 inches and a width of 1 5/9?

Calculus
A rectangle is bounded by the xaxis and the semicircle y=ã(25x^2). Question is, what length and width should the rectangle have so that its area is a maximum, and what is the maxuimum area? Area= length*width = 2x*y=

math
the length of a rectangle is 8cm more than the width and its area is 172cm^2 .Find a) the width od the rectangle; b) the length of the diagonal of the rectangle, giving your answer correct to 2 decimal places

Math
The length of a rectangle is 5 inches less than 3 times the width. The perimeter of the rectangle is 14 inches. Find the length and width of the rectangle. I did this: Length 3x5; width 3x Then I did guess and check and came up
You can view more similar questions or ask a new question.