A polling company took 5 polls in the week before an election. It showed that a mayoral candidate would get 66%, 56%, 55%, and 63% of the voters. That candidate received 64% of the total votes during the actual election. Find the percent error in the average of the company's polling results, to the nearest tenth of a percent. Show your work.

Question

A polling company took 5 polls in the week before an election. It showed that a mayoral candidate would get 66%, 56%, 55%, and 63% of the voters. That candidate received 64% of the total votes during the actual election. Find the percent error in the average of the company's polling results, to the nearest tenth of a percent. Show your work.

Answer 1

average = (1/4)(66+56+55+63)

= 60

percent error = 100 (64 - 60)/64
= 6.25 %

Answer 2

To find the percent error in the average of the polling results, we need to compare the average of the polling results to the actual election result and calculate the difference as a percentage of the actual election result.

First, let's calculate the average of the polling results:

Average = (66% + 56% + 55% + 63%) / 4 = 240% / 4 = 60%

Next, we calculate the difference between the average of the polling results and the actual election result:

Difference = 64% - 60% = 4%

Finally, we calculate the percent error by dividing the difference by the actual election result and multiplying by 100:

Percent Error = (4% / 64%) * 100 ≈ 6.25%

Therefore, the percent error in the average of the polling results is approximately 6.25%.