Assume you started with a 0.642 gram sample of Sodium Bicarbonate and aster adding an excess of hydrochloric acid and carrying out the experiment correctly, you calculateed there was a 94.8% yield of sodium chloride. What was the experimental yield of sodium chloride in the experiment?
I did get the theoretical yield of sodim chloride? I got 0.3115g
Please help me
The question is worded poorly. I assume you want to calculate the GRAMS of NaCl produced in the experiment with a 94.8% yield.
%yield =(actual yield/theor yield)*100
98.4 = (actual/theor)*100
0.984 = actual/0.3115
Solve for actual yield
yes i do understand that 0.3115 us the actual yield the theoretical yield but i need the the experimental yield of soduim chloride
That's the actual yield.
Theoretical yield is 0.3115 and I'm assuming that is correct.
% yield is 98.4% of that; therefore, experimentally you will collect 0.984 x 0.3115 g = ? grams NaCl.
1. Potassium, a silvery metal, reacts with bromine, a corrosive, reddish liquid, to yield potassium bromide, a white solid. Write the balanced equation, and identify the oxidizing and reducing agents.
To calculate the experimental yield of sodium chloride, we need to know the actual amount of sodium chloride obtained in the experiment. Given that the percent yield is 94.8%, we can use the following formula:
Experimental yield = Theoretical yield * Percent yield / 100
Substituting the given values, we have:
Experimental yield = 0.3115 g * 94.8 / 100
To calculate this, you simply multiply 0.3115 by 94.8 and then divide the result by 100.
So, the experimental yield of sodium chloride in the experiment would be calculated as follows:
0.3115 g * 94.8 / 100 = 0.2949 g
Therefore, the experimental yield of sodium chloride in your experiment would be approximately 0.2949 grams.