math

How do I do this? Without a calculator, determine two angles between 0 degrees and 360 degrees that have a cosine of negative square root 3 over 2.

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  1. 30, 60, 90 triangle
    1, sqrt 3, 2

    sin 30 = 1/2
    cos 30 = sqrt 3/2

    cos is negative in quad 2 and quad 3
    so
    180 - 30 = 150 degrees
    180 + 30 = 210 degrees

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