A cylindrical water tower with a conical top and hemispheric bottom needs to be painted. If the cost is 2.19 per square foot, how much does it cost (to the nearest dollar) to paint the tank?
surface area of tower
= surface area of "sleeve" of cylinder + half a sphere + lateral surface area of cone
Since you don't give me any dimensions, that is all I can give you.
Oops, sorry, I forgot to give the dimensions.
The dimensions of the cone are 2ft. high and 3.2 ft. at the slant.
The dimensions of the cylinder are 5ft. across and 6 ft. tall.
I wasn't sure if I needed to figure Total Surface Area or Lateral Surface Area, or both.
To find the cost of painting the water tower, we need to calculate the surface area of the different components and then multiply it by the cost per square foot.
1. Calculate the surface area of the cylindrical part:
The formula for the surface area of a cylinder is given by A = 2πrh, where r is the radius and h is the height. Since the top and bottom of the cylindrical part are hemispheres, we only need to consider the curved surface area of the cylinder. The height of the cylinder is the total height minus the height of the conical top.
2. Calculate the surface area of the conical top:
The formula for the surface area of a cone is given by A = πrl, where r is the radius of the base and l is the slant height.
3. Calculate the surface area of the hemispheric bottom:
The formula for the surface area of a hemisphere is given by A = 2πr^2.
Once we have calculated the surface area of each component, we can add them together and multiply by the cost per square foot to find the total cost of painting the tank.
Remember to round the answer to the nearest dollar.
Do you know the dimensions of the water tower? Specifically, we need the radius and height of the cylindrical part, as well as the radius and slant height of the conical part.