1) A racing car has a mass of 1525 kg. What is its kinetic energy if it has a speed of 35 m/s?
2) How much potential energy does Tim,with mass 60.0 kg, gain when he climbs a gymnasium rope a distance of 3.5 m?
-Benchmark Review-
KE = 1/2 m v^2
PE = mgh g = 9.8 m/s^2
Just substitute your values directly.
1) To find the kinetic energy of the racing car, we can use the formula:
Kinetic Energy (KE) = 1/2 * mass * velocity^2
Given:
Mass (m) = 1525 kg
Velocity (v) = 35 m/s
Using the formula, we can calculate:
KE = 1/2 * 1525 kg * (35 m/s)^2
= 1/2 * 1525 kg * 1225 m^2/s^2
= 91562.5 kg·m^2/s^2
Therefore, the kinetic energy of the racing car is 91562.5 kg·m^2/s^2.
2) The potential energy gained by Tim while climbing the gymnasium rope can be calculated using the formula:
Potential Energy (PE) = mass * acceleration due to gravity * height
Given:
Mass (m) = 60.0 kg
Acceleration due to gravity (g) = 9.8 m/s^2
Height (h) = 3.5 m
Substituting the values into the formula, we get:
PE = 60.0 kg * 9.8 m/s^2 * 3.5 m
= 2058 Joules
Therefore, Tim gains 2058 Joules of potential energy while climbing the gymnasium rope.
To calculate the kinetic energy of an object, you can use the equation: KE = (1/2) * mass * velocity^2.
1) For the racing car, given that its mass is 1525 kg and its speed is 35 m/s, you can use the equation to calculate its kinetic energy:
KE = (1/2) * 1525 kg * (35 m/s)^2
KE = 0.5 * 1525 kg * 1225 m^2/s^2
KE = 929687.5 joules
Therefore, the kinetic energy of the racing car is 929,687.5 joules.
To calculate the potential energy of an object, you can use the equation: PE = mass * gravity * height.
2) For Tim climbing the gymnasium rope with a mass of 60.0 kg and climbing a distance of 3.5 m, you can use the equation to calculate his potential energy:
PE = 60.0 kg * 9.8 m/s^2 * 3.5 m
PE = 2058 joules
Therefore, Tim gains 2058 joules of potential energy while climbing the gymnasium rope.
I hope this helps! Let me know if you have any further questions.