I cant figure this out! Can someone please tell me were my mistake is?? :)
- a man is 3 times as old as his son. In 11 years time he will be twice as old as his son will be.
Let s represent sons age in years now
I did: present man: 3s son: s
In 11 years man: 2(s+11). Son: s+11
I tried alot and finally got the answer :) thanks anyways
I always found that these are easy when the information is restated in different cases
present:
son's age --- x
man' age ---- 3x
in 11 years from now:
son's age = x+11
man's age = 3x+11
it said, at that time the man is twice as old as his son
3x+11 = 2(x+11)
3x + 11 = 2x + 22
x = 11
The son is now 11, and the man is now 33
check:
now son is 11, man is 33
in 11 years:
son is 22 , man is 44
is the man twice as old as his son at that time ?
YES.
A man is four times as old as his son. In 6 years he will be three times as old. The son present age is what?
To help you spot any mistakes, let's walk through the problem and the steps you've taken so far.
1. Let's represent the son's current age with the variable s.
2. According to the information given, the man is 3 times as old as his son. So the man's current age would be 3s.
3. In 11 years, the man's age will be 3s + 11.
4. Likewise, in 11 years, the son's age will be s + 11.
5. The problem states that in 11 years, the man will be twice as old as his son will be. So, we can set up an equation: 3s + 11 = 2(s + 11).
6. By simplifying the equation, we get 3s + 11 = 2s + 22.
7. Subtracting 2s from both sides of the equation, we have s + 11 = 22.
8. Subtracting 11 from both sides, the equation becomes s = 11.
So, your mistake seems to be in step 7. Instead of subtracting 2s from both sides of the equation, it appears that you mistakenly subtracted s from both sides.
To find the correct answer, follow the steps above and solve for s.