7750 Joules of energy is added to a 325 grams stone at 24.0 degrees centigrade. The temperature increases by 75.0 degrees centigrade. What is the specific heat of the stone?
To find the specific heat of the stone, we can use the formula:
q = m * c * ΔT
Where:
- q is the heat energy added to the stone (7750 J in this case)
- m is the mass of the stone (325 g)
- c is the specific heat of the stone (what we want to find)
- ΔT is the change in temperature (75.0 °C)
We can rearrange the formula to solve for c:
c = q / (m * ΔT)
Now let's substitute the values into the formula:
c = 7750 J / (325 g * 75.0 °C)
To get the specific heat in J/g°C, we need to convert the mass from grams to kilograms:
c = 7750 J / (0.325 kg * 75.0 °C)
Calculating this, we find:
c ≈ 32 J/g°C
Therefore, the specific heat of the stone is approximately 32 J/g°C.