Algebra

(x-3)/5 = (x-3)/x
The x-3 is over the 5 and the other x-3 is over the x...

I know to cross multiply so I would get
5(x-3)= x(x-3) But then would i just divide (x-3) by both sides?

I would assume that's what to do,
but the only reason I ask is because my book says the answer is 3,5

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  1. 5x-3/5x (x2-3)

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