Chemistry

Calculate the volume of 1.0 M copper(II) sulfate solution required to completely react with 1.0 g of Fe(s) according to this equation: 2 Fe(s) + 3 Cu^2+ (aq) --> 2 Fe^3+ (aq) + 3 Cu (s).

the copper in the reactant has a charge of 2+ and the iron in the product has a charge of 3+..sorry for the confusion. can anyone walk me through this? I'm unsure where to begin.

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  1. mols Fe = grams/atomic mass
    Use the coefficients in the balanced equation to convert mols Fe to mols Cu^2+ (i.e. CuSO4).
    Then M CuSO4 = mols CuSO4/L CuSO4. You have M and mols, solve for L. Convert to mL if needed.

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  2. 10 mL

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  3. 1.0

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