If you have 1.90 mol of H_2 , how many grams of NH_3 can be produced?

asked by Nancy
  1. N2 + 3H2 => 2NH3
    mols H2 = 1.90
    mols H2 x (2 mols NH3/3 mol H2) = 1.90 x 2/3 = ? mol NH3.
    Then g = mols NH3 x molar mass NH3.

    posted by DrBob222

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