Calculus

At what value of x does the graph of y=9x^(1/3)+x^2 have a point of inflection?

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asked by Raul
  1. y' = 3x^(-2/3) + 2x
    y'' = -2x^(-5/3) + 2
    = 0 for a pt of infl.

    2/x^(5/3) = 2
    x^(5/3) = 1
    x = 1
    then y = 9(1) + 1 = 10

    the point of inflection is (1,10)

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    posted by Reiny

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