In American roulette where there are 38 numbers, how many possible outcomes can you have if you bet on an odd number?
I'm not sure I understand your post.
Odd numbers/38 = ?
There is only one outcome. Are you asking for the probability of getting an odd number?
To determine the number of possible outcomes when betting on an odd number in American roulette, we need to understand the total number of outcomes and the number of odd numbers on the roulette wheel.
In American roulette, there are 38 numbers on the wheel. These numbers include 1 to 36, as well as 0 and 00. Of these 38 numbers, 18 are odd numbers (1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31, 33, and 35).
To determine the number of outcomes when betting on an odd number, we simply need to count the number of possible outcomes (18) since all the odd numbers are considered winning outcomes in this scenario.
Therefore, when betting on an odd number in American roulette, there are 18 possible outcomes.