Hello,
Can someone tell me if I have the correct answer?
Thank You
my answer: B
A circuit contains two devices that are connected in parallel. If the resistance of one of these devices is 12 ohms and the resistance of the other device is 4 ohms, the total resistance of the two devices is?
A.0.333 ohms
B.3 ohms
I don't think the question is exactly clear. The TOTAL resistance is obviously 12 + 4= 16 ohms; however, the resistance in the circuit is 3.0 ohms and your answer is correct. I think we can assume the person who wrote the question meant the total resistance in the circuit (in which they are parallel).
if the total resistance of two circuits in parallel is 4 ohms and one circuit has twice the resistance of the other, find the resistance of each circuit
To find the total resistance of two devices connected in parallel, you can use the following formula:
1/RTotal = 1/R1 + 1/R2
Where RTotal is the total resistance, R1 is the resistance of the first device, and R2 is the resistance of the second device.
Now, let's calculate the total resistance of the two devices in question.
Given that R1 = 12 ohms and R2 = 4 ohms, we can substitute these values into the formula:
1/RTotal = 1/12 + 1/4
To simplify this expression, we need to find a common denominator for 12 and 4, which is 12. Rewrite the expression:
1/RTotal = 1/12 + 3/12
Now, add the fractions:
1/RTotal = 4/12
Simplify the fraction:
1/RTotal = 1/3
To get the value of RTotal, we need to reciprocate both sides of the equation:
RTotal = 3 ohms
Therefore, the correct answer is B. The total resistance of the two devices is 3 ohms