# trig

If sin theta is equal to 5/13 and theta is an angle in quadrant II find the value of cos theta, sec theta, tan theta, csc theta, cot theta.

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1. make a sketch of your triangle
since sinØ = opposite /hypotenuse = 5/13
opposite = 5 and hypotenuse = 13
by Pythagoras:
x^2 + 5^2 = 13^2
x^2 +25 = 169
x^2 = 144
x = ± 12 , but in quadrant II, x = - 12

sinØ = 5/13 , cscØ = 13/5
cosØ = -12/13 , secØ = - 13/12
tanØ = 5/-12 = -5/12 , cot Ø = -12/5

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posted by Reiny
2. 6 6-6sin(0=?

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posted by saurabh

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