# algebra

If a rocket is propelled upward from ground level, it's height in meters after t seconds is given by h=-9.8t^2+88.2t. During what interval of time will the rocket be higher than 137.2m?

h=9.8t^2+ 88.2t
I divided both sides by -9.8 which gave me
t^2=-9

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1. The equation:
137.2 = -9.8t^2 + 88.2t

Divide both sides by -9.8 (whatever operation you do to one side of an equation you must do to the other side as well):

(137.2)/-9.8 = (-9.8t^2 + 88.2t)/-9.8

-14 = t^2 - 9

Set the equation equal to 0:

0 = t^2 - 9 + 14

Try to factor:

0 = (t - 7)(t - 2)

Set the factors equal to 0:
t - 7 = 0
t - 2 = 0

Therefore, the two solutions are t = 2 and t = 7.

Interval: 2 < t < 7

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