A stone propelled from a catapult with a speed of 50m/s attains a height of 100m.Calculate:(a)the time of flight?
time of fligt
t=2*√2H/g
=2*√2*100/10
=2*√200/10
=2*√20
=2*4.47
=8.94s
A. time of flight
t=2*√2H/g
=2*√2*100/10
=2*√200/10
=2*√20
=2*4.47
=8.94s
B. The angle of projection
sinø=0.8944
Ø= sin–¹(0.8944)
Ø=63.4314654⁰
Ø ≈ 63.43⁰
C. Range
R=u²sin2ø/g
R=? u=50 , ø=63.4⁰, g= 10
= 50²*sin(2*63.4⁰)/10
=2500*sin(126.8⁰)/10
=250*0.8007
=200.2m
R≈200m
A. time of flight
t=2*√2H/g
=2*√2*100/10
=2*√200/10
=2*√20
=2*4.47
=8.94s
B. The angle of projection
sinø=0.8944
Ø= sin–¹(0.8944)
Ø=63.4314654⁰
Ø ≈ 63.43⁰
C. Range
R=u²sin2ø/g
R=? u=50 , ø=63.4⁰, g= 10
= 50²*sin(2*63.4⁰)/10
=2500*sin(126.8⁰)/10
=250*0.8007
=200.2m
R≈200m
T=8.945
Which Formular Will You Use To Get The Angle Of Projection?
A STONE IS PROPELLED FROM A CATAPULT WITH A SPEED OF 500MS ATTAINS THE HEIGHT OF 100M.CALCULATE,a:THE TIME OF FLIGHT,b:THE ANGLE OF PROJECTION,c:THE RANGE ATTAINED.
Tether=sin-1(Tg/2u)
am asking question a stone propelled from a catapult with a speed of 50 m/s attains a height of 100m calculate (a)the range attained
I THINK ANONYMOUS MAY BE CORRECT
I don't get why it is multiplied by 2
how are we going to calculate the angle of projection and the range attained
Thanks so much for solving this problem already, i appreciate u very much
Anonymous are right
How did you get the tita
Exactly how did you get the theta
pls how did u solve the angle of projection
Thanks so much i appreciate
A stone propeller from a catopon often a gift of 100m calculate
What is the formula used in time of flight
Thank you very well
thanks
A how do i calculate a stone propelled from a catapult with a speed of 50ms attains a height of 100m.calcute the time of flight
(a)the angle of projection (b) the range attained
Yggdo
Just as long as anything else that goes up 100 meters and falls
Which is twice as long as it takes to fall 100 meters
h = (1/2) g t^2
100 = 4.9 t^2
t = 4.52 seconds to fall
so about 9 seconds