chemistry

I have a problem like this:
CHCl3 + Cl2 = CCl4 +HCL
This is the rate table:
CHCL3 Cl2 Initial Rate
.010 .010 .0035
.020 .010 .0069
.020 .020 .0098
.040 .040 .027

They want me to find the rate constant and the rate law.

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asked by Nancy
  1. However, when I try to find the rate constant I get 3.5. My book says 3.5^-.5. I don't know how they got this.
    .0069= (.010)^.5(.020)=approx 3.5
    but the book says 3.5M^-1/2*s-1

    Also I am wondering if there are three reactants in a problem, is there any difference how it is done?

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    posted by Nancy
  2. If you will calculate k for ALL trials, all come out to about 3.5 and from your data 3.5 surely is correct. The only suggestion I have is that sometimes they place an exponent at the top of the table so that all of the rates would be x 10^-5 or something like that.

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