An aluminium alloy bar with a Young's modulus of 70GPa is under a tensile stress of 10MPa, Which of thefollowing is the equal to the strain in the bar?
A 0.0014
B 7.0x10 3
c 700
D 1.4x10 -4
To find the strain in the aluminum alloy bar, we can use the formula:
strain = stress / Young's modulus
Here, the stress is given as 10MPa (mega pascals), and the Young's modulus is given as 70GPa (giga pascals).
First, let's convert the stress from MPa to Pa:
10MPa = 10 * 10^6 Pa
Now, let's plug the values into the formula to find the strain:
strain = (10 * 10^6 Pa) / (70 * 10^9 Pa)
Dividing the values, we get:
strain = 0.000142857
This value is equivalent to 1.4x10^-4.
Therefore, the correct answer is D) 1.4x10^-4.