Drawls,
How did you get 2h. and then the 2a/h from.Can you help me understand it when you get a chance.
Directions: Solve each literal equation for the indicated variable.
A=1/2h(B+b) (For b) Area of a trapezoid
For Further Reading
math,algebra - drwls, Monday, December 18, 2006 at 10:26am
It is just a matter of algebraic manipulation.
A=(1/2)h(B+b)
Multiply both sides of the equation by 2/h.
B+b = 2A/h
b = (2A/h) - B
Thank you.
Sure! I'd be happy to help you understand the steps involved in solving the given equation for variable b.
The equation we start with is: A = (1/2)h(B + b)
To solve for b, we want to isolate it on one side of the equation. Here's how we can do that:
Step 1: Multiply both sides of the equation by 2/h to get rid of the fraction (1/2) and h on the right side:
(2/h)A = (2/h)(1/2)h(B + b)
(2A)/h = B + b
Step 2: Now, we need to isolate b on one side of the equation. Since b is being added to B, we can subtract B from both sides of the equation:
(2A)/h - B = b
So, the final equation is:
b = (2A/h) - B
This means that to solve for b, you take 2 times the value of A, divide it by h, and then subtract the value of B.
I hope this explanation clarifies how we arrived at the equation b = (2A/h) - B. If you have any further questions, feel free to ask!