find all real or imaginery solutions.
I came up with {-6,6}, is this correct or have I missed something?
-4k^2+144=0
-144=-144
-4k^2/-4=-144/-4
K^2=36
x=+or- sqrt 36
x=+or-6
Hi:
You are absolutely correct.
Regards,
Rich B.
15.2
Your solution of {-6, 6} is correct for the equation -4k^2 + 144 = 0.
To explain how to find all the real or imaginary solutions, here are the steps:
1. Start with the equation: -4k^2 + 144 = 0.
2. Move the constant term (in this case, 144) to the other side of the equation to isolate the variable: -4k^2 = -144.
3. Divide both sides of the equation by -4 to solve for k^2: k^2 = 36.
4. Take the square root of both sides of the equation to solve for k: k = ±√36.
5. Simplify the square root of 36: k = ±6.
Therefore, the solutions for k can be either -6 or 6, so your solution of {-6, 6} is correct.