A man was given $x. He spent 50 cents a day. How much money had he left after
A) 10 days?
B) 2 weeks?
C) t days?
1st term = x
2nd term = x-.5
3rd term = x - 2(.5)
....
10th term = x - 9(.5) = x - .45
...
14th term = x - 13(.5) = x - 6.5
t th term = x - (t-1)(.5)
I assume you are studying sequences and series.
Do you recognize the arithmetic sequence pattern ?
To find out how much money the man had left after a given number of days, we need to subtract the amount he spent from the initial amount he was given.
Let's break down the problem step by step:
A) After 10 days:
The amount the man spent each day is 50 cents. So, the total amount he spent in 10 days is 10 * 50 cents = $5.
To find out how much money he had left, we subtract $5 from the initial amount (x):
Money left = x - $5.
B) After 2 weeks:
Since there are 7 days in a week, two weeks consist of 2 * 7 = 14 days.
The total amount he spent in 2 weeks is 14 * 50 cents = $7.
To find the money left, we subtract $7 from the initial amount (x):
Money left = x - $7.
C) After t days:
In this case, the number of days is represented by the variable 't'.
The total amount he spent in t days is t * 50 cents = $0.50t.
To find the money left, we subtract $0.50t from the initial amount (x):
Money left = x - $0.50t.
So, the amount of money the man had left after:
A) 10 days: x - $5.
B) 2 weeks: x - $7.
C) t days: x - $0.50t.