Finding domain
f(x)=1/x^2-5
Can't remember how to solve, your help is appreciated:-)
If X^2-5 is the denom, then the domain would be all X such that the denom does not equal 0.
So find when x^2-5=0
x=sqrt(5) (Both positive and negative)
So the domain is all real numbers, such that X does not equal +- sqrt (5)