Precalculus need help!!
Quadratic Formula
1.) x+6/x=7
2.) 4x/x+4 + 3/x1 = 15/x^2+3x4
3.) x+3/x  2/x+3 = 6/x^2+3x
formula:
B+ sqrt B^2 + (4)(a)(c)/2a
f u only wanted to use the formula it's not necessary though.
please help me! it's going to pass tomorrow!! please!

your formula should say:
x = (b ± √(b^2  4ac) )/(2a)
1. x + 6/x = 7
each term by x
x^2 + 6 = 7x
x^2 + 7x + 6 = 0
it factors, no need for the formula
(x+1)(x+6) = 0
x = 1 or x = 6
2. you probably meant:
4x/(x+4) + 3/(x1) = 15/(x^2 + 3x  4)
4x/(x+4) + 3/(x1) = 15/((x1)(x+4) )
multiply each term by (x+4)(x1) , the LCD
4x(x1) + 3(x+4) = 15
4x^2  4 + 3x + 12 = 15
4x^2 + 3x 7 = 0
x = (3 ±√(94(4)(7)) )/8
= (3 ±√121)/8 = (3 ± 11)/8
x = 1 or x = 7/4
or.... we could have factored it again
(x1)(4x + 7) = 0
x = 1 or x = 7/4
3. again, brackets will be essential.
(x+3)/x  2/(x+3) = 6/( x(x+3))
the LCD is x(x+3) , so multiply each term by x(x+3)
You can take it from there.posted by Reiny
Respond to this Question
Similar Questions

Math
Use the quadratic formula to solve each of the following quadratic equations... 1. 2x^25x=3 2. 3x^22x+1=0 Rearrange the equation in quadratic formula form. 2x^2 5x 3 = 0 Then use the formula. Tell me what you don't understand 
math,algebra
can someone help me out factor out this 0=16t^2122t+180 i have so far this but the last one i am not sure 8(2t^214t + ?) you need to use the quadratic formula: b(+or)[sqrt(b^24ac)/2a] so you are saying that i don't have to 
Math
Solve for the zeros of the function using the quadratic formula. 3x^2=4x+6 I know what the quadratic formula is but when I put it into the formula I keep getting an error on the graphing calculator. 
Calculus
Please look at my work below: Solve the initialvalue problem. y'' + 4y' + 6y = 0 , y(0) = 2 , y'(0) = 4 r^2+4r+6=0, r=(16 +/ Sqrt(4^24(1)(6)))/2(1) r=(16 +/ Sqrt(8)) r=8 +/ Sqrt(2)*i, alpha=8, Beta=Sqrt(2) y(0)=2, 
math
use the quadratic formula to solve this equation. 4x^28x+3=5 use the formula x=b + or  the sqrt of b^24ac/2a yes, the 2a divides into all. Memorize it. 
math
15t^2+7t=2 The quadratic formula tells you that the solutions are: t = [b +/sqrt (b^2  4ac]/ (2a) In this case, a = 15, b = 7 and c = 2 solve the equation for t. What values for t will you get when you substitute the values 
PreAlgebra
Please help to solve to find x,y 1. y=7x3 2. 4x+2y=8 Take the value of y in the first formula and substitute it for y in the second formula. Solve the second formula for x. Once x is found, solve for y in the second formula. 
Ap algebra
2+3X^2X^3=0 by use quadratic formula. The answer of textbook is 3.19 So I solved and came out a wrong answer What I did factor out (X+3)X^2+2=0 Then By quadratic formula, a=1,b=0,c=2. Thus I got sqrt(8)/2 
mathcalculus
solve equation x^22x6 using quadratic formula. i not get how to do this and it says quadratic formula. 
algebra
I worked the problem out, but could you check my work over and see if it's correct? I used the quadratic formula. 2x^2+10x+11 a=2 b=10 c=11 x=10(plus or minus) sqrt 10^24(2)(11) over 2(2) 10(plus or minus) sqrt 100  8(11) over