chemistry

A compound with the percent composition shown below has a molar mass of 60.10g/mol. Find its molecular formula:

C, 39.97%
H, 13.41%
N, 46.62%

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  1. Take a 100 g sample. That gives you
    39.97 g C
    13.4 g H
    46.62 g N

    Convert to mols.
    39.97/12 = mols C
    13.41/1 = mols H
    46.62/14 = mols N.

    Now find the ratio of the elements to each other with the smallest being 1.00. The easy way to do that is to divide the smallest number by itself, then divide the other numbers by that same small number.
    Post your work if you get stuck.

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  2. Sorry for the intrusion, chemistry: timecode 6:44 I gave K one of your previous answers but it didn't suffice...

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  3. C H N
    MASS 39.97g 13.41g 46.62
    #mol 3.33 13.41 3.33
    ratio 1 4 1
    empirical formular CH4N
    empirical mass 30
    (CH4N)2=C2H8N2
    THUS THE MOLECULAR FORMULA

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  4. What is the empirical formula of 54.5% carbon 9.09% hydrogen and 36.4% oxygen

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