Josh hit a baseball straight up into the air. The equation below describes the height of the ball (h), in meters, as a function of time (t) in seconds.
h(t) = -9.8t² + 30t + 1.5
What is the height of the ball after 3 seconds?
i keep getting -195.9
h(3) = -9.8(9) + 30(3) + 1.5
= 3.3
I don't have the foggiest clue how you came up with -195.8
I tried different permutations of the arithmetic, but no luck.
h(t) = -9.8(3)^2+30(3)+1.5 = 3.3 meters
To find the height of the ball after 3 seconds, substitute t = 3 into the given equation for h(t):
h(3) = -9.8(3)² + 30(3) + 1.5
Simplifying:
h(3) = -9.8(9) + 90 + 1.5
h(3) = -88.2 + 90 + 1.5
h(3) = 2.3
Therefore, the height of the ball after 3 seconds is 2.3 meters.
To find the height of the ball after 3 seconds, you need to substitute the value of 3 into the equation h(t) = -9.8t² + 30t + 1.5.
So, plug in t = 3:
h(3) = -9.8(3)² + 30(3) + 1.5
Now, let's simplify the equation:
h(3) = -9.8(9) + 90 + 1.5
h(3) = -88.2 + 90 + 1.5
h(3) = 1.3
Therefore, the height of the ball after 3 seconds is approximately 1.3 meters, not -195.9. It seems you might have made an error in your calculations.