What volume of 0.1 M NaOH is required to neutralize 30 mL of 0.1 M HCl?

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  1. Calculate the number of moles for HCl in a 30mL sample of 0.1M HCl

    30 x10^-3 L*(0.1M)=moles of HCl

    The number of moles of HCl/the molarity of NaOH will give you the volume needed in L.

    volume in L=moles of HCl/0.1 M NaOH

    *** Multiply the volume by 10^3 if you need to report the volume in mLs.

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